Separate equations from the combined oneFactorise ax2+2hxy+by2=0, or solve bm2+2hm+a=0 for the slopes m=y/xLocked
Sum and product of slopesm1+m2=−b2h,m1m2=ba; use them to find a missing coefficient from a condition on the slopesLocked
Angle between the linestanθ=a+b2h2−ab; perpendicular when a+b=0, coincident when h2=abLocked
Pairs perpendicular or at an angle to given linesThrough the origin, perpendicular to the pair ax2+2hxy+by2=0:bx2−2hxy+ay2=0; at an angle α to a line, from tanαLocked
Triangles formed with a third lineFind where the pair meets the third line, then the angles or the area of the triangle; equal angles of 60° make it equilateralLocked
Bisectors of the angles between the linesThe joint equation of the bisectors of ax2+2hxy+by2=0 is h(x2−y2)=(a−b)xyLocked
General equation0 / 2
When a general equation is a pair of linesax2+2hxy+by2+2gx+2fy+c=0 is a pair of lines when ahghbfgfc=0 and h2≥abLocked
Angle, parallel pair and point of intersectionThe angle depends only on a,h,b; the pair through a point parallel to ax2+2hxy+by2=0
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the lines meet where the two separated lines cross